Integrand size = 25, antiderivative size = 91 \[ \int \frac {x}{(d+e x)^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\frac {4 x}{15 d^3 e \sqrt {d^2-e^2 x^2}}+\frac {1}{5 e^2 (d+e x)^2 \sqrt {d^2-e^2 x^2}}-\frac {2}{15 d e^2 (d+e x) \sqrt {d^2-e^2 x^2}} \]
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Time = 0.02 (sec) , antiderivative size = 91, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {807, 673, 197} \[ \int \frac {x}{(d+e x)^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx=-\frac {2}{15 d e^2 (d+e x) \sqrt {d^2-e^2 x^2}}+\frac {1}{5 e^2 (d+e x)^2 \sqrt {d^2-e^2 x^2}}+\frac {4 x}{15 d^3 e \sqrt {d^2-e^2 x^2}} \]
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Rule 197
Rule 673
Rule 807
Rubi steps \begin{align*} \text {integral}& = \frac {1}{5 e^2 (d+e x)^2 \sqrt {d^2-e^2 x^2}}+\frac {2 \int \frac {1}{(d+e x) \left (d^2-e^2 x^2\right )^{3/2}} \, dx}{5 e} \\ & = \frac {1}{5 e^2 (d+e x)^2 \sqrt {d^2-e^2 x^2}}-\frac {2}{15 d e^2 (d+e x) \sqrt {d^2-e^2 x^2}}+\frac {4 \int \frac {1}{\left (d^2-e^2 x^2\right )^{3/2}} \, dx}{15 d e} \\ & = \frac {4 x}{15 d^3 e \sqrt {d^2-e^2 x^2}}+\frac {1}{5 e^2 (d+e x)^2 \sqrt {d^2-e^2 x^2}}-\frac {2}{15 d e^2 (d+e x) \sqrt {d^2-e^2 x^2}} \\ \end{align*}
Time = 0.33 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.76 \[ \int \frac {x}{(d+e x)^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\frac {\sqrt {d^2-e^2 x^2} \left (d^3+2 d^2 e x+8 d e^2 x^2+4 e^3 x^3\right )}{15 d^3 e^2 (d-e x) (d+e x)^3} \]
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Time = 0.38 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.70
method | result | size |
gosper | \(\frac {\left (-e x +d \right ) \left (4 e^{3} x^{3}+8 d \,e^{2} x^{2}+2 d^{2} e x +d^{3}\right )}{15 \left (e x +d \right ) d^{3} e^{2} \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}\) | \(64\) |
trager | \(\frac {\left (4 e^{3} x^{3}+8 d \,e^{2} x^{2}+2 d^{2} e x +d^{3}\right ) \sqrt {-e^{2} x^{2}+d^{2}}}{15 d^{3} \left (e x +d \right )^{3} e^{2} \left (-e x +d \right )}\) | \(66\) |
default | \(\frac {-\frac {1}{3 d e \left (x +\frac {d}{e}\right ) \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}-\frac {-2 \left (x +\frac {d}{e}\right ) e^{2}+2 d e}{3 e \,d^{3} \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}}{e^{2}}-\frac {d \left (-\frac {1}{5 d e \left (x +\frac {d}{e}\right )^{2} \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}+\frac {3 e \left (-\frac {1}{3 d e \left (x +\frac {d}{e}\right ) \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}-\frac {-2 \left (x +\frac {d}{e}\right ) e^{2}+2 d e}{3 e \,d^{3} \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}\right )}{5 d}\right )}{e^{3}}\) | \(262\) |
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Time = 0.27 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.27 \[ \int \frac {x}{(d+e x)^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\frac {e^{4} x^{4} + 2 \, d e^{3} x^{3} - 2 \, d^{3} e x - d^{4} - {\left (4 \, e^{3} x^{3} + 8 \, d e^{2} x^{2} + 2 \, d^{2} e x + d^{3}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{15 \, {\left (d^{3} e^{6} x^{4} + 2 \, d^{4} e^{5} x^{3} - 2 \, d^{6} e^{3} x - d^{7} e^{2}\right )}} \]
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\[ \int \frac {x}{(d+e x)^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\int \frac {x}{\left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac {3}{2}} \left (d + e x\right )^{2}}\, dx \]
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none
Time = 0.21 (sec) , antiderivative size = 138, normalized size of antiderivative = 1.52 \[ \int \frac {x}{(d+e x)^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\frac {1}{5 \, {\left (\sqrt {-e^{2} x^{2} + d^{2}} e^{4} x^{2} + 2 \, \sqrt {-e^{2} x^{2} + d^{2}} d e^{3} x + \sqrt {-e^{2} x^{2} + d^{2}} d^{2} e^{2}\right )}} - \frac {2}{15 \, {\left (\sqrt {-e^{2} x^{2} + d^{2}} d e^{3} x + \sqrt {-e^{2} x^{2} + d^{2}} d^{2} e^{2}\right )}} + \frac {4 \, x}{15 \, \sqrt {-e^{2} x^{2} + d^{2}} d^{3} e} \]
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Result contains complex when optimal does not.
Time = 0.31 (sec) , antiderivative size = 177, normalized size of antiderivative = 1.95 \[ \int \frac {x}{(d+e x)^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx=-\frac {-\frac {32 i \, \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right )}{d^{3}} - \frac {15}{d^{3} \sqrt {\frac {2 \, d}{e x + d} - 1} \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right )} - \frac {3 \, d^{12} {\left (\frac {2 \, d}{e x + d} - 1\right )}^{\frac {5}{2}} \mathrm {sgn}\left (\frac {1}{e x + d}\right )^{4} \mathrm {sgn}\left (e\right )^{4} + 5 \, d^{12} {\left (\frac {2 \, d}{e x + d} - 1\right )}^{\frac {3}{2}} \mathrm {sgn}\left (\frac {1}{e x + d}\right )^{4} \mathrm {sgn}\left (e\right )^{4} - 15 \, d^{12} \sqrt {\frac {2 \, d}{e x + d} - 1} \mathrm {sgn}\left (\frac {1}{e x + d}\right )^{4} \mathrm {sgn}\left (e\right )^{4}}{d^{15} \mathrm {sgn}\left (\frac {1}{e x + d}\right )^{5} \mathrm {sgn}\left (e\right )^{5}}}{120 \, e {\left | e \right |}} \]
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Time = 11.81 (sec) , antiderivative size = 65, normalized size of antiderivative = 0.71 \[ \int \frac {x}{(d+e x)^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx=\frac {\sqrt {d^2-e^2\,x^2}\,\left (d^3+2\,d^2\,e\,x+8\,d\,e^2\,x^2+4\,e^3\,x^3\right )}{15\,d^3\,e^2\,{\left (d+e\,x\right )}^3\,\left (d-e\,x\right )} \]
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